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633345242543341 is a prime number
BaseRepresentation
bin1001000000000001100010111…
…0001100111011010011101101
310002001111012202220121120100221
42100000120232030323103231
51131003212024042341331
610123002442053051341
7250255453346261626
oct22000305614732355
93061435686546327
10633345242543341
11173892233159459
125b04a674326b51
132125227a81a173
14b2581051baa4d
154d34b6ac47711
hex240062e33b4ed

633345242543341 has 2 divisors, whose sum is σ = 633345242543342. Its totient is φ = 633345242543340.

The previous prime is 633345242543281. The next prime is 633345242543381. The reversal of 633345242543341 is 143345242543336.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 419806087288900 + 213539155254441 = 20489170^2 + 14612979^2 .

It is a cyclic number.

It is not a de Polignac number, because 633345242543341 - 225 = 633345208988909 is a prime.

It is a super-2 number, since 2×6333452425433412 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (633345242543381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 316672621271670 + 316672621271671.

It is an arithmetic number, because the mean of its divisors is an integer number (316672621271671).

Almost surely, 2633345242543341 is an apocalyptic number.

It is an amenable number.

633345242543341 is a deficient number, since it is larger than the sum of its proper divisors (1).

633345242543341 is an equidigital number, since it uses as much as digits as its factorization.

633345242543341 is an evil number, because the sum of its binary digits is even.

The product of its digits is 37324800, while the sum is 52.

The spelling of 633345242543341 in words is "six hundred thirty-three trillion, three hundred forty-five billion, two hundred forty-two million, five hundred forty-three thousand, three hundred forty-one".