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63422034739937 is a prime number
BaseRepresentation
bin11100110101110100101111…
…10110100000001011100001
322022120002100122110221010022
432122322113312200023201
531303101311343134222
6342515402555043225
716234043100332036
oct1632722766401341
9268502318427108
1063422034739937
1119232152224455
127143747140515
132950897b12c83
14119390001738d
1574eb453d2042
hex39ae97da02e1

63422034739937 has 2 divisors, whose sum is σ = 63422034739938. Its totient is φ = 63422034739936.

The previous prime is 63422034739907. The next prime is 63422034739939. The reversal of 63422034739937 is 73993743022436.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 50675021212321 + 12747013527616 = 7118639^2 + 3570296^2 .

It is a cyclic number.

It is not a de Polignac number, because 63422034739937 - 28 = 63422034739681 is a prime.

Together with 63422034739939, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 63422034739937.

It is not a weakly prime, because it can be changed into another prime (63422034739939) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31711017369968 + 31711017369969.

It is an arithmetic number, because the mean of its divisors is an integer number (31711017369969).

Almost surely, 263422034739937 is an apocalyptic number.

It is an amenable number.

63422034739937 is a deficient number, since it is larger than the sum of its proper divisors (1).

63422034739937 is an equidigital number, since it uses as much as digits as its factorization.

63422034739937 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 123451776, while the sum is 62.

The spelling of 63422034739937 in words is "sixty-three trillion, four hundred twenty-two billion, thirty-four million, seven hundred thirty-nine thousand, nine hundred thirty-seven".