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637105542413 is a prime number
BaseRepresentation
bin10010100010101100111…
…00110001010100001101
32020220110222110220121212
421101112130301110031
540414243004324123
61204403210504205
764013032520654
oct11212634612415
92226428426555
10637105542413
1122621651882a
12a3585435065
134810415c972
1422b9c28019b
151188c6ac878
hex945673150d

637105542413 has 2 divisors, whose sum is σ = 637105542414. Its totient is φ = 637105542412.

The previous prime is 637105542389. The next prime is 637105542467. The reversal of 637105542413 is 314245501736.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 548722414564 + 88383127849 = 740758^2 + 297293^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-637105542413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (637105542113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 318552771206 + 318552771207.

It is an arithmetic number, because the mean of its divisors is an integer number (318552771207).

Almost surely, 2637105542413 is an apocalyptic number.

It is an amenable number.

637105542413 is a deficient number, since it is larger than the sum of its proper divisors (1).

637105542413 is an equidigital number, since it uses as much as digits as its factorization.

637105542413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 302400, while the sum is 41.

The spelling of 637105542413 in words is "six hundred thirty-seven billion, one hundred five million, five hundred forty-two thousand, four hundred thirteen".