Base | Representation |
---|---|
bin | 101110011011000001001… |
… | …1101001011010110101011 |
3 | 211120221110011100221121201 |
4 | 1130312002131023112223 |
5 | 1314013140032340243 |
6 | 21323010320345031 |
7 | 1225645451502151 |
oct | 134660235132653 |
9 | 24527404327551 |
10 | 6380215121323 |
11 | 203a91a11664a |
12 | 870641175177 |
13 | 373861a43424 |
14 | 180b384a73d1 |
15 | b0e6d95a04d |
hex | 5cd8274b5ab |
6380215121323 has 2 divisors, whose sum is σ = 6380215121324. Its totient is φ = 6380215121322.
The previous prime is 6380215121317. The next prime is 6380215121339. The reversal of 6380215121323 is 3231215120836.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 6380215121323 - 213 = 6380215113131 is a prime.
It is not a weakly prime, because it can be changed into another prime (6380215121383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3190107560661 + 3190107560662.
It is an arithmetic number, because the mean of its divisors is an integer number (3190107560662).
Almost surely, 26380215121323 is an apocalyptic number.
6380215121323 is a deficient number, since it is larger than the sum of its proper divisors (1).
6380215121323 is an equidigital number, since it uses as much as digits as its factorization.
6380215121323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 37.
The spelling of 6380215121323 in words is "six trillion, three hundred eighty billion, two hundred fifteen million, one hundred twenty-one thousand, three hundred twenty-three".
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