Search a number
-
+
6382486604047 is a prime number
BaseRepresentation
bin101110011100000100111…
…0110001100100100001111
3211121011022110120020010111
41130320021312030210033
51314032313032312142
621324023542220451
71226055653001601
oct134701166144417
924534273506114
106382486604047
11204088532a1a4
12870b75a24727
13373b34512448
14180cb2031171
15b1053096e17
hex5ce09d8c90f

6382486604047 has 2 divisors, whose sum is σ = 6382486604048. Its totient is φ = 6382486604046.

The previous prime is 6382486604023. The next prime is 6382486604069. The reversal of 6382486604047 is 7404066842836.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 6382486604047 - 27 = 6382486603919 is a prime.

It is a super-2 number, since 2×63824866040472 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 6382486603982 and 6382486604000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (6382486604147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3191243302023 + 3191243302024.

It is an arithmetic number, because the mean of its divisors is an integer number (3191243302024).

Almost surely, 26382486604047 is an apocalyptic number.

6382486604047 is a deficient number, since it is larger than the sum of its proper divisors (1).

6382486604047 is an equidigital number, since it uses as much as digits as its factorization.

6382486604047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 37158912, while the sum is 58.

The spelling of 6382486604047 in words is "six trillion, three hundred eighty-two billion, four hundred eighty-six million, six hundred four thousand, forty-seven".