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638462013251 is a prime number
BaseRepresentation
bin10010100101001110100…
…11010010111101000011
32021000222111220202210112
421102213103102331003
540430032233411001
61205145544421535
764061453366306
oct11224723227503
92230874822715
10638462013251
11226852186407
12a38a37778ab
134828c1aa42a
1422c8a4a0b3d
151191b804cbb
hex94a74d2f43

638462013251 has 2 divisors, whose sum is σ = 638462013252. Its totient is φ = 638462013250.

The previous prime is 638462013227. The next prime is 638462013253. The reversal of 638462013251 is 152310264836.

638462013251 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-638462013251 is a prime.

Together with 638462013253, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 638462013199 and 638462013208.

It is not a weakly prime, because it can be changed into another prime (638462013253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 319231006625 + 319231006626.

It is an arithmetic number, because the mean of its divisors is an integer number (319231006626).

Almost surely, 2638462013251 is an apocalyptic number.

638462013251 is a deficient number, since it is larger than the sum of its proper divisors (1).

638462013251 is an equidigital number, since it uses as much as digits as its factorization.

638462013251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 207360, while the sum is 41.

The spelling of 638462013251 in words is "six hundred thirty-eight billion, four hundred sixty-two million, thirteen thousand, two hundred fifty-one".