Base | Representation |
---|---|
bin | 101110100101110101100… |
… | …0000110101000110110011 |
3 | 211200011102000212001222112 |
4 | 1131023223000311012303 |
5 | 1314403223144244243 |
6 | 21341411314555535 |
7 | 1230430213034135 |
oct | 135135300650663 |
9 | 24604360761875 |
10 | 6403444134323 |
11 | 204975a304955 |
12 | 875044598bab |
13 | 375ac43a7532 |
14 | 181cdd56b055 |
15 | b187ce05818 |
hex | 5d2eb0351b3 |
6403444134323 has 2 divisors, whose sum is σ = 6403444134324. Its totient is φ = 6403444134322.
The previous prime is 6403444134299. The next prime is 6403444134331. The reversal of 6403444134323 is 3234314443046.
6403444134323 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 6403444134323 - 210 = 6403444133299 is a prime.
It is not a weakly prime, because it can be changed into another prime (6403444134343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3201722067161 + 3201722067162.
It is an arithmetic number, because the mean of its divisors is an integer number (3201722067162).
Almost surely, 26403444134323 is an apocalyptic number.
6403444134323 is a deficient number, since it is larger than the sum of its proper divisors (1).
6403444134323 is an equidigital number, since it uses as much as digits as its factorization.
6403444134323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 995328, while the sum is 41.
Adding to 6403444134323 its reverse (3234314443046), we get a palindrome (9637758577369).
The spelling of 6403444134323 in words is "six trillion, four hundred three billion, four hundred forty-four million, one hundred thirty-four thousand, three hundred twenty-three".
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