Base | Representation |
---|---|
bin | 101110100101110101100… |
… | …0000110101000111000111 |
3 | 211200011102000212002000021 |
4 | 1131023223000311013013 |
5 | 1314403223144244333 |
6 | 21341411315000011 |
7 | 1230430213034164 |
oct | 135135300650707 |
9 | 24604360762007 |
10 | 6403444134343 |
11 | 204975a304973 |
12 | 875044599007 |
13 | 375ac43a7549 |
14 | 181cdd56b06b |
15 | b187ce0582d |
hex | 5d2eb0351c7 |
6403444134343 has 2 divisors, whose sum is σ = 6403444134344. Its totient is φ = 6403444134342.
The previous prime is 6403444134331. The next prime is 6403444134389. The reversal of 6403444134343 is 3434314443046.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 6403444134343 - 237 = 6266005180871 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 6403444134343.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6403444134323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3201722067171 + 3201722067172.
It is an arithmetic number, because the mean of its divisors is an integer number (3201722067172).
Almost surely, 26403444134343 is an apocalyptic number.
6403444134343 is a deficient number, since it is larger than the sum of its proper divisors (1).
6403444134343 is an equidigital number, since it uses as much as digits as its factorization.
6403444134343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1990656, while the sum is 43.
Adding to 6403444134343 its reverse (3434314443046), we get a palindrome (9837758577389).
The spelling of 6403444134343 in words is "six trillion, four hundred three billion, four hundred forty-four million, one hundred thirty-four thousand, three hundred forty-three".
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