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64034763114253 is a prime number
BaseRepresentation
bin11101000111101010000010…
…10011110000011100001101
322101201122220202000101200111
432203311001103300130031
531343121143324124003
6344105055234400021
716326234060513061
oct1643650123603415
9271648822011614
1064034763114253
1119448a99438a68
127222448730011
1329965b579a3c9
1411b542891baa1
15760a578e9e6d
hex3a3d414f070d

64034763114253 has 2 divisors, whose sum is σ = 64034763114254. Its totient is φ = 64034763114252.

The previous prime is 64034763114167. The next prime is 64034763114277. The reversal of 64034763114253 is 35241136743046.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 53935701992649 + 10099061121604 = 7344093^2 + 3177902^2 .

It is a cyclic number.

It is not a de Polignac number, because 64034763114253 - 217 = 64034762983181 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 64034763114197 and 64034763114206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (64034763117253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32017381557126 + 32017381557127.

It is an arithmetic number, because the mean of its divisors is an integer number (32017381557127).

Almost surely, 264034763114253 is an apocalyptic number.

It is an amenable number.

64034763114253 is a deficient number, since it is larger than the sum of its proper divisors (1).

64034763114253 is an equidigital number, since it uses as much as digits as its factorization.

64034763114253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4354560, while the sum is 49.

Adding to 64034763114253 its reverse (35241136743046), we get a palindrome (99275899857299).

The spelling of 64034763114253 in words is "sixty-four trillion, thirty-four billion, seven hundred sixty-three million, one hundred fourteen thousand, two hundred fifty-three".