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6408120894713 is a prime number
BaseRepresentation
bin101110101000000000111…
…0001010000010011111001
3211200121110222000010011022
41131100001301100103321
51314442312422112323
621343503342112225
71230654131611106
oct135200161202371
924617428003138
106408120894713
11205073a20518a
12875b2a87b675
1337638b28c485
14182224729aad
15b1a537ac4c8
hex5d401c504f9

6408120894713 has 2 divisors, whose sum is σ = 6408120894714. Its totient is φ = 6408120894712.

The previous prime is 6408120894671. The next prime is 6408120894737. The reversal of 6408120894713 is 3174980218046.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5237195634064 + 1170925260649 = 2288492^2 + 1082093^2 .

It is a cyclic number.

It is not a de Polignac number, because 6408120894713 - 28 = 6408120894457 is a prime.

It is not a weakly prime, because it can be changed into another prime (6408120894613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3204060447356 + 3204060447357.

It is an arithmetic number, because the mean of its divisors is an integer number (3204060447357).

Almost surely, 26408120894713 is an apocalyptic number.

It is an amenable number.

6408120894713 is a deficient number, since it is larger than the sum of its proper divisors (1).

6408120894713 is an equidigital number, since it uses as much as digits as its factorization.

6408120894713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2322432, while the sum is 53.

The spelling of 6408120894713 in words is "six trillion, four hundred eight billion, one hundred twenty million, eight hundred ninety-four thousand, seven hundred thirteen".