Base | Representation |
---|---|
bin | 101110101000111001111… |
… | …0101100010101111011001 |
3 | 211200210102100000111122112 |
4 | 1131101303311202233121 |
5 | 1320010222330341101 |
6 | 21344421304002105 |
7 | 1231052430201155 |
oct | 135216365425731 |
9 | 24623370014575 |
10 | 6410034621401 |
11 | 2051531486394 |
12 | 876383760335 |
13 | 3766048bac28 |
14 | 182366968065 |
15 | b1b167cc6bb |
hex | 5d473d62bd9 |
6410034621401 has 2 divisors, whose sum is σ = 6410034621402. Its totient is φ = 6410034621400.
The previous prime is 6410034621349. The next prime is 6410034621451. The reversal of 6410034621401 is 1041264300146.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4357760625625 + 2052273995776 = 2087525^2 + 1432576^2 .
It is a cyclic number.
It is not a de Polignac number, because 6410034621401 - 238 = 6135156714457 is a prime.
It is a super-2 number, since 2×64100346214012 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (6410034621451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3205017310700 + 3205017310701.
It is an arithmetic number, because the mean of its divisors is an integer number (3205017310701).
Almost surely, 26410034621401 is an apocalyptic number.
It is an amenable number.
6410034621401 is a deficient number, since it is larger than the sum of its proper divisors (1).
6410034621401 is an equidigital number, since it uses as much as digits as its factorization.
6410034621401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 32.
Adding to 6410034621401 its reverse (1041264300146), we get a palindrome (7451298921547).
The spelling of 6410034621401 in words is "six trillion, four hundred ten billion, thirty-four million, six hundred twenty-one thousand, four hundred one".
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