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64102013 is a prime number
BaseRepresentation
bin1111010010000…
…1111001111101
311110121201102122
43310201321331
5112402231023
610205532325
71405600223
oct364417175
9143551378
1064102013
1133202878
12195740a5
13103850b1
148728b13
1559632c8
hex3d21e7d

64102013 has 2 divisors, whose sum is σ = 64102014. Its totient is φ = 64102012.

The previous prime is 64101971. The next prime is 64102037. The reversal of 64102013 is 31020146.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 60248644 + 3853369 = 7762^2 + 1963^2 .

It is a cyclic number.

It is not a de Polignac number, because 64102013 - 210 = 64100989 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 64101982 and 64102000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (64102043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32051006 + 32051007.

It is an arithmetic number, because the mean of its divisors is an integer number (32051007).

Almost surely, 264102013 is an apocalyptic number.

It is an amenable number.

64102013 is a deficient number, since it is larger than the sum of its proper divisors (1).

64102013 is an equidigital number, since it uses as much as digits as its factorization.

64102013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 64102013 is about 8006.3732738363. The cubic root of 64102013 is about 400.2124142638.

Adding to 64102013 its reverse (31020146), we get a palindrome (95122159).

The spelling of 64102013 in words is "sixty-four million, one hundred two thousand, thirteen".