Base | Representation |
---|---|
bin | 101110101001001101110… |
… | …0101001011010111110101 |
3 | 211200212010210201101101201 |
4 | 1131102123211023113311 |
5 | 1320013104030420041 |
6 | 21345011403452501 |
7 | 1231105104661363 |
oct | 135223345132765 |
9 | 24625123641351 |
10 | 6410701420021 |
11 | 2051843909028 |
12 | 87652ab27131 |
13 | 3766acaa4122 |
14 | 1823cb33c633 |
15 | b1b550e2631 |
hex | 5d49b94b5f5 |
6410701420021 has 2 divisors, whose sum is σ = 6410701420022. Its totient is φ = 6410701420020.
The previous prime is 6410701420007. The next prime is 6410701420069. The reversal of 6410701420021 is 1200241070146.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6362431132996 + 48270287025 = 2522386^2 + 219705^2 .
It is a cyclic number.
It is not a de Polignac number, because 6410701420021 - 211 = 6410701417973 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6410701420001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3205350710010 + 3205350710011.
It is an arithmetic number, because the mean of its divisors is an integer number (3205350710011).
Almost surely, 26410701420021 is an apocalyptic number.
It is an amenable number.
6410701420021 is a deficient number, since it is larger than the sum of its proper divisors (1).
6410701420021 is an equidigital number, since it uses as much as digits as its factorization.
6410701420021 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2688, while the sum is 28.
Adding to 6410701420021 its reverse (1200241070146), we get a palindrome (7610942490167).
The spelling of 6410701420021 in words is "six trillion, four hundred ten billion, seven hundred one million, four hundred twenty thousand, twenty-one".
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