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64112037397 is a prime number
BaseRepresentation
bin111011101101011000…
…000000111000010101
320010111002002221121121
4323231120000320111
52022300140144042
645241435243541
74426520216632
oct735530007025
9203432087547
1064112037397
112520a634681
1210512ba95b1
136079648405
143162a4d189
151a03759367
hexeed600e15

64112037397 has 2 divisors, whose sum is σ = 64112037398. Its totient is φ = 64112037396.

The previous prime is 64112037377. The next prime is 64112037413. The reversal of 64112037397 is 79373021146.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 51979896081 + 12132141316 = 227991^2 + 110146^2 .

It is a cyclic number.

It is not a de Polignac number, because 64112037397 - 215 = 64112004629 is a prime.

It is a super-2 number, since 2×641120373972 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (64112037377) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32056018698 + 32056018699.

It is an arithmetic number, because the mean of its divisors is an integer number (32056018699).

Almost surely, 264112037397 is an apocalyptic number.

It is an amenable number.

64112037397 is a deficient number, since it is larger than the sum of its proper divisors (1).

64112037397 is an equidigital number, since it uses as much as digits as its factorization.

64112037397 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 190512, while the sum is 43.

The spelling of 64112037397 in words is "sixty-four billion, one hundred twelve million, thirty-seven thousand, three hundred ninety-seven".