Base | Representation |
---|---|
bin | 10010101010010000010… |
… | …11100111011111101101 |
3 | 2021021221121210012200002 |
4 | 21111020023213133231 |
5 | 41001044222211023 |
6 | 1210313444114045 |
7 | 64215366462233 |
oct | 11251013473755 |
9 | 2237847705602 |
10 | 641161132013 |
11 | 227a07820276 |
12 | a4317695925 |
13 | 485cc445a1c |
14 | 23064b44953 |
15 | 11a28763b28 |
hex | 95482e77ed |
641161132013 has 2 divisors, whose sum is σ = 641161132014. Its totient is φ = 641161132012.
The previous prime is 641161131973. The next prime is 641161132093. The reversal of 641161132013 is 310231161146.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 352364521609 + 288796610404 = 593603^2 + 537398^2 .
It is a cyclic number.
It is not a de Polignac number, because 641161132013 - 214 = 641161115629 is a prime.
It is a super-2 number, since 2×6411611320132 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (641161132093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 320580566006 + 320580566007.
It is an arithmetic number, because the mean of its divisors is an integer number (320580566007).
Almost surely, 2641161132013 is an apocalyptic number.
It is an amenable number.
641161132013 is a deficient number, since it is larger than the sum of its proper divisors (1).
641161132013 is an equidigital number, since it uses as much as digits as its factorization.
641161132013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 29.
Adding to 641161132013 its reverse (310231161146), we get a palindrome (951392293159).
The spelling of 641161132013 in words is "six hundred forty-one billion, one hundred sixty-one million, one hundred thirty-two thousand, thirteen".
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