6411724800 has 576 divisors, whose sum is σ = 24170328000. Its totient is φ = 1495203840.

The previous prime is 6411724769. The next prime is 6411724801. The reversal of 6411724800 is 84271146.

It is a super-3 number, since 3×6411724800³ (a number of 30 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (6411724801) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 337459191 + ... + 337459209.

It is an arithmetic number, because the mean of its divisors is an integer number (41962375).

Almost surely, 2^6411724800 is an apocalyptic number.

6411724800 is a gapful number since it is divisible by the number (60) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 6411724800, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (12085164000).

6411724800 is an abundant number, since it is smaller than the sum of its proper divisors (17758603200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

6411724800 is a wasteful number, since it uses less digits than its factorization.

6411724800 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 93 (or 42 counting only the distinct ones).

The product of its (nonzero) digits is 10752, while the sum is 33.

The square root of 6411724800 is about 80073.2464684679. The cubic root of 6411724800 is about 1857.7686272164.

Adding to 6411724800 its reverse (84271146), we get a palindrome (6495995946).

The spelling of 6411724800 in words is "six billion, four hundred eleven million, seven hundred twenty-four thousand, eight hundred".