Base | Representation |
---|---|
bin | 111011101110000101… |
… | …011011001000011011 |
3 | 20010111220111201211201 |
4 | 323232011123020123 |
5 | 2022311212111103 |
6 | 45242542335031 |
7 | 4430023336324 |
oct | 735605331033 |
9 | 203456451751 |
10 | 64123941403 |
11 | 252163252a5 |
12 | 10516b8a477 |
13 | 607bc557c2 |
14 | 316446b44b |
15 | 1a0480b51d |
hex | eee15b21b |
64123941403 has 2 divisors, whose sum is σ = 64123941404. Its totient is φ = 64123941402.
The previous prime is 64123941361. The next prime is 64123941407. The reversal of 64123941403 is 30414932146.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-64123941403 is a prime.
It is a super-2 number, since 2×641239414032 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (64123941407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32061970701 + 32061970702.
It is an arithmetic number, because the mean of its divisors is an integer number (32061970702).
Almost surely, 264123941403 is an apocalyptic number.
64123941403 is a deficient number, since it is larger than the sum of its proper divisors (1).
64123941403 is an equidigital number, since it uses as much as digits as its factorization.
64123941403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 37.
The spelling of 64123941403 in words is "sixty-four billion, one hundred twenty-three million, nine hundred forty-one thousand, four hundred three".
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