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6412451413 is a prime number
BaseRepresentation
bin1011111100011011…
…00011111001010101
3121112220011021122111
411332031203321111
5101113041421123
62540145031021
7314622636424
oct57615437125
917486137574
106412451413
1127a0730725
1212ab625471
137b2679964
1444b8d52bb
15277e5a90d
hex17e363e55

6412451413 has 2 divisors, whose sum is σ = 6412451414. Its totient is φ = 6412451412.

The previous prime is 6412451399. The next prime is 6412451431. The reversal of 6412451413 is 3141542146.

Together with next prime (6412451431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6384329604 + 28121809 = 79902^2 + 5303^2 .

It is a cyclic number.

It is not a de Polignac number, because 6412451413 - 221 = 6410354261 is a prime.

It is a super-2 number, since 2×64124514132 = 82239066248171393138, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (6412451443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3206225706 + 3206225707.

It is an arithmetic number, because the mean of its divisors is an integer number (3206225707).

Almost surely, 26412451413 is an apocalyptic number.

It is an amenable number.

6412451413 is a deficient number, since it is larger than the sum of its proper divisors (1).

6412451413 is an equidigital number, since it uses as much as digits as its factorization.

6412451413 is an evil number, because the sum of its binary digits is even.

The product of its digits is 11520, while the sum is 31.

The square root of 6412451413 is about 80077.7835170280. The cubic root of 6412451413 is about 1857.8388021895.

Adding to 6412451413 its reverse (3141542146), we get a palindrome (9553993559).

The spelling of 6412451413 in words is "six billion, four hundred twelve million, four hundred fifty-one thousand, four hundred thirteen".