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64131983 is a prime number
BaseRepresentation
bin1111010010100…
…1001110001111
311110200020112122
43310221032033
5112404210413
610210323155
71406053466
oct364511617
9143606478
1064131983
1133223343
12195894bb
1310395926
1487359dd
15596c108
hex3d2938f

64131983 has 2 divisors, whose sum is σ = 64131984. Its totient is φ = 64131982.

The previous prime is 64131943. The next prime is 64132031. The reversal of 64131983 is 38913146.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 64131983 - 210 = 64130959 is a prime.

It is a super-2 number, since 2×641319832 = 8225822487024578, which contains 22 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (64131943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32065991 + 32065992.

It is an arithmetic number, because the mean of its divisors is an integer number (32065992).

Almost surely, 264131983 is an apocalyptic number.

64131983 is a deficient number, since it is larger than the sum of its proper divisors (1).

64131983 is an equidigital number, since it uses as much as digits as its factorization.

64131983 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 15552, while the sum is 35.

The square root of 64131983 is about 8008.2446890689. The cubic root of 64131983 is about 400.2747757858.

The spelling of 64131983 in words is "sixty-four million, one hundred thirty-one thousand, nine hundred eighty-three".