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64138937250463 is a prime number
BaseRepresentation
bin11101001010101100000101…
…00100100011001010011111
322102002121210211000211100121
432211112002210203022133
531401323020414003323
6344225004311535411
716336612441201645
oct1645260244431237
9272077724024317
1064138937250463
1119489196a85409
12723a68038a567
1329a3377ccb41a
1411ba4ac0a1195
15763603305a5d
hex3a558292329f

64138937250463 has 2 divisors, whose sum is σ = 64138937250464. Its totient is φ = 64138937250462.

The previous prime is 64138937250439. The next prime is 64138937250511. The reversal of 64138937250463 is 36405273983146.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-64138937250463 is a prime.

It is a super-2 number, since 2×641389372504632 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (64138937256463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32069468625231 + 32069468625232.

It is an arithmetic number, because the mean of its divisors is an integer number (32069468625232).

It is a 1-persistent number, because it is pandigital, but 2⋅64138937250463 = 128277874500926 is not.

Almost surely, 264138937250463 is an apocalyptic number.

64138937250463 is a deficient number, since it is larger than the sum of its proper divisors (1).

64138937250463 is an equidigital number, since it uses as much as digits as its factorization.

64138937250463 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 78382080, while the sum is 61.

The spelling of 64138937250463 in words is "sixty-four trillion, one hundred thirty-eight billion, nine hundred thirty-seven million, two hundred fifty thousand, four hundred sixty-three".