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641405224252099 is a prime number
BaseRepresentation
bin1001000111010110101100101…
…0100011000111001011000011
310010010000201222220011111010001
42101311223022203013023003
51133032240344402031344
610152053254153220431
7252046666250354506
oct22165531243071303
93103021886144101
10641405224252099
1117640a47876621a
125bb30767a01717
13216b833a135a88
14b45626db0b13d
154e2464d9eaed4
hex2475aca8c72c3

641405224252099 has 2 divisors, whose sum is σ = 641405224252100. Its totient is φ = 641405224252098.

The previous prime is 641405224252031. The next prime is 641405224252141. The reversal of 641405224252099 is 990252422504146.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 641405224252099 - 27 = 641405224251971 is a prime.

It is a super-2 number, since 2×6414052242520992 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (641405224652099) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 320702612126049 + 320702612126050.

It is an arithmetic number, because the mean of its divisors is an integer number (320702612126050).

Almost surely, 2641405224252099 is an apocalyptic number.

641405224252099 is a deficient number, since it is larger than the sum of its proper divisors (1).

641405224252099 is an equidigital number, since it uses as much as digits as its factorization.

641405224252099 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12441600, while the sum is 55.

The spelling of 641405224252099 in words is "six hundred forty-one trillion, four hundred five billion, two hundred twenty-four million, two hundred fifty-two thousand, ninety-nine".