Base | Representation |
---|---|
bin | 1001000111010110101100101… |
… | …0100011000111001011000011 |
3 | 10010010000201222220011111010001 |
4 | 2101311223022203013023003 |
5 | 1133032240344402031344 |
6 | 10152053254153220431 |
7 | 252046666250354506 |
oct | 22165531243071303 |
9 | 3103021886144101 |
10 | 641405224252099 |
11 | 17640a47876621a |
12 | 5bb30767a01717 |
13 | 216b833a135a88 |
14 | b45626db0b13d |
15 | 4e2464d9eaed4 |
hex | 2475aca8c72c3 |
641405224252099 has 2 divisors, whose sum is σ = 641405224252100. Its totient is φ = 641405224252098.
The previous prime is 641405224252031. The next prime is 641405224252141. The reversal of 641405224252099 is 990252422504146.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 641405224252099 - 27 = 641405224251971 is a prime.
It is a super-2 number, since 2×6414052242520992 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (641405224652099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 320702612126049 + 320702612126050.
It is an arithmetic number, because the mean of its divisors is an integer number (320702612126050).
Almost surely, 2641405224252099 is an apocalyptic number.
641405224252099 is a deficient number, since it is larger than the sum of its proper divisors (1).
641405224252099 is an equidigital number, since it uses as much as digits as its factorization.
641405224252099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12441600, while the sum is 55.
The spelling of 641405224252099 in words is "six hundred forty-one trillion, four hundred five billion, two hundred twenty-four million, two hundred fifty-two thousand, ninety-nine".
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