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641413511 is a prime number
BaseRepresentation
bin100110001110110…
…011000110000111
31122200221011220222
4212032303012013
52303200213021
6143351414555
721615632144
oct4616630607
91580834828
10641413511
112aa074512
1215a98445b
13a2b6892b
14612873cb
153b49d6ab
hex263b3187

641413511 has 2 divisors, whose sum is σ = 641413512. Its totient is φ = 641413510.

The previous prime is 641413483. The next prime is 641413523. The reversal of 641413511 is 115314146.

641413511 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-641413511 is a prime.

It is a super-2 number, since 2×6414135112 = 822822584186694242, which contains 22 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (641413711) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 320706755 + 320706756.

It is an arithmetic number, because the mean of its divisors is an integer number (320706756).

Almost surely, 2641413511 is an apocalyptic number.

641413511 is a deficient number, since it is larger than the sum of its proper divisors (1).

641413511 is an equidigital number, since it uses as much as digits as its factorization.

641413511 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1440, while the sum is 26.

The square root of 641413511 is about 25326.1428369975. The cubic root of 641413511 is about 862.4078505766.

Adding to 641413511 its reverse (115314146), we get a palindrome (756727657).

It can be divided in two parts, 6414135 and 11, that added together give a palindrome (6414146).

The spelling of 641413511 in words is "six hundred forty-one million, four hundred thirteen thousand, five hundred eleven".