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641436004264331 is a prime number
BaseRepresentation
bin1001000111011000011111010…
…1001011100010100110001011
310010010010200110000012010010002
42101312013311023202212023
51133033241414042424311
610152115344331513215
7252052136101221503
oct22166076513424613
93103120400163102
10641436004264331
11176421533228a61
125bb36717bb880b
13216bb203ca3073
14b45794d99aa03
154e25350d4e93b
hex24761f52e298b

641436004264331 has 2 divisors, whose sum is σ = 641436004264332. Its totient is φ = 641436004264330.

The previous prime is 641436004264273. The next prime is 641436004264369. The reversal of 641436004264331 is 133462400634146.

641436004264331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 641436004264331 - 234 = 641418824395147 is a prime.

It is a super-2 number, since 2×6414360042643312 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (641436034264331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 320718002132165 + 320718002132166.

It is an arithmetic number, because the mean of its divisors is an integer number (320718002132166).

Almost surely, 2641436004264331 is an apocalyptic number.

641436004264331 is a deficient number, since it is larger than the sum of its proper divisors (1).

641436004264331 is an equidigital number, since it uses as much as digits as its factorization.

641436004264331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2985984, while the sum is 47.

Adding to 641436004264331 its reverse (133462400634146), we get a palindrome (774898404898477).

The spelling of 641436004264331 in words is "six hundred forty-one trillion, four hundred thirty-six billion, four million, two hundred sixty-four thousand, three hundred thirty-one".