Base | Representation |
---|---|
bin | 100110001111011… |
… | …001100100101001 |
3 | 1122201020012010002 |
4 | 212033121210221 |
5 | 2303220233423 |
6 | 143355032345 |
7 | 21620156501 |
oct | 4617314451 |
9 | 1581205102 |
10 | 641571113 |
11 | 2aa171967 |
12 | 15aa3b6b5 |
13 | a2bc25a1 |
14 | 612c8a01 |
15 | 3b4d0228 |
hex | 263d9929 |
641571113 has 2 divisors, whose sum is σ = 641571114. Its totient is φ = 641571112.
The previous prime is 641571079. The next prime is 641571127. The reversal of 641571113 is 311175146.
It is a happy number.
641571113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 554932249 + 86638864 = 23557^2 + 9308^2 .
It is a cyclic number.
It is not a de Polignac number, because 641571113 - 222 = 637376809 is a prime.
It is a super-2 number, since 2×6415711132 = 823226986072117538, which contains 22 as substring.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (641571713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 320785556 + 320785557.
It is an arithmetic number, because the mean of its divisors is an integer number (320785557).
Almost surely, 2641571113 is an apocalyptic number.
It is an amenable number.
641571113 is a deficient number, since it is larger than the sum of its proper divisors (1).
641571113 is an equidigital number, since it uses as much as digits as its factorization.
641571113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2520, while the sum is 29.
The square root of 641571113 is about 25329.2540948209. The cubic root of 641571113 is about 862.4784789981.
The spelling of 641571113 in words is "six hundred forty-one million, five hundred seventy-one thousand, one hundred thirteen".
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