Base | Representation |
---|---|
bin | 11101001011010101010111… |
… | …00110101010000101111111 |
3 | 22102011202000102002211121012 |
4 | 32211222223212222011333 |
5 | 31402203413212133341 |
6 | 344243111435225435 |
7 | 16341325611564524 |
oct | 1645525346520577 |
9 | 272152012084535 |
10 | 64161100505471 |
11 | 1949762a616992 |
12 | 7242a268a827b |
13 | 29a549a9105b8 |
14 | 11bb5b17bb14b |
15 | 763e9de310eb |
hex | 3a5aab9aa17f |
64161100505471 has 2 divisors, whose sum is σ = 64161100505472. Its totient is φ = 64161100505470.
The previous prime is 64161100505393. The next prime is 64161100505531. The reversal of 64161100505471 is 17450500116146.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 64161100505471 - 218 = 64161100243327 is a prime.
It is a super-3 number, since 3×641611005054713 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (64161100505371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32080550252735 + 32080550252736.
It is an arithmetic number, because the mean of its divisors is an integer number (32080550252736).
Almost surely, 264161100505471 is an apocalyptic number.
64161100505471 is a deficient number, since it is larger than the sum of its proper divisors (1).
64161100505471 is an equidigital number, since it uses as much as digits as its factorization.
64161100505471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 100800, while the sum is 41.
The spelling of 64161100505471 in words is "sixty-four trillion, one hundred sixty-one billion, one hundred million, five hundred five thousand, four hundred seventy-one".
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