Base | Representation |
---|---|
bin | 10010101100000000001… |
… | …10100000111111000000 |
3 | 2021101101000011000212220 |
4 | 21112000012200333000 |
5 | 41010004411144340 |
6 | 1210550520451040 |
7 | 64250551104366 |
oct | 11260006407700 |
9 | 2241330130786 |
10 | 642099318720 |
11 | 228349364892 |
12 | a4539919a80 |
13 | 4871b91c7a2 |
14 | 231135a1636 |
15 | 11a80cd4ed0 |
hex | 95801a0fc0 |
642099318720 has 448 divisors, whose sum is σ = 2178666118656. Its totient is φ = 159664046080.
The previous prime is 642099318691. The next prime is 642099318733. The reversal of 642099318720 is 27813990246.
It is a Cunningham number, because it is equal to 8013112-1.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1307737675 + ... + 1307738165.
Almost surely, 2642099318720 is an apocalyptic number.
642099318720 is a gapful number since it is divisible by the number (60) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 642099318720, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1089333059328).
642099318720 is an abundant number, since it is smaller than the sum of its proper divisors (1536566799936).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
642099318720 is a wasteful number, since it uses less digits than its factorization.
642099318720 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1108 (or 1098 counting only the distinct ones).
The product of its (nonzero) digits is 1306368, while the sum is 51.
The spelling of 642099318720 in words is "six hundred forty-two billion, ninety-nine million, three hundred eighteen thousand, seven hundred twenty".
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