Base | Representation |
---|---|
bin | 111011110011011110… |
… | …111001101010000101 |
3 | 20010202012220220021101 |
4 | 323303132321222011 |
5 | 2023002403143432 |
6 | 45255535420101 |
7 | 4432203203356 |
oct | 736336715205 |
9 | 203665826241 |
10 | 64214506117 |
11 | 25262461973 |
12 | 10541384631 |
13 | 60949447a8 |
14 | 31724c3d2d |
15 | 1a0c74a4e7 |
hex | ef37b9a85 |
64214506117 has 2 divisors, whose sum is σ = 64214506118. Its totient is φ = 64214506116.
The previous prime is 64214506091. The next prime is 64214506123. The reversal of 64214506117 is 71160541246.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 54230299876 + 9984206241 = 232874^2 + 99921^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-64214506117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (64214506217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32107253058 + 32107253059.
It is an arithmetic number, because the mean of its divisors is an integer number (32107253059).
Almost surely, 264214506117 is an apocalyptic number.
It is an amenable number.
64214506117 is a deficient number, since it is larger than the sum of its proper divisors (1).
64214506117 is an equidigital number, since it uses as much as digits as its factorization.
64214506117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 37.
The spelling of 64214506117 in words is "sixty-four billion, two hundred fourteen million, five hundred six thousand, one hundred seventeen".
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