Base | Representation |
---|---|
bin | 101110101111001100100… |
… | …1100100001011110110001 |
3 | 211202002021222122010021102 |
4 | 1131132121030201132301 |
5 | 1320220410323220213 |
6 | 21354534134134145 |
7 | 1232041315462106 |
oct | 135363114413661 |
9 | 24662258563242 |
10 | 6423546304433 |
11 | 2057235477885 |
12 | 878b147b1355 |
13 | 377978ca564b |
14 | 182c8924aaad |
15 | b2157b04158 |
hex | 5d7993217b1 |
6423546304433 has 2 divisors, whose sum is σ = 6423546304434. Its totient is φ = 6423546304432.
The previous prime is 6423546304363. The next prime is 6423546304463. The reversal of 6423546304433 is 3344036453246.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5983150818304 + 440395486129 = 2446048^2 + 663623^2 .
It is a cyclic number.
It is not a de Polignac number, because 6423546304433 - 28 = 6423546304177 is a prime.
It is not a weakly prime, because it can be changed into another prime (6423546304463) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3211773152216 + 3211773152217.
It is an arithmetic number, because the mean of its divisors is an integer number (3211773152217).
Almost surely, 26423546304433 is an apocalyptic number.
It is an amenable number.
6423546304433 is a deficient number, since it is larger than the sum of its proper divisors (1).
6423546304433 is an equidigital number, since it uses as much as digits as its factorization.
6423546304433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7464960, while the sum is 47.
The spelling of 6423546304433 in words is "six trillion, four hundred twenty-three billion, five hundred forty-six million, three hundred four thousand, four hundred thirty-three".
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