Base | Representation |
---|---|
bin | 111011110101110101… |
… | …110100100110011111 |
3 | 20010211222100220112221 |
4 | 323311311310212133 |
5 | 2023043020203101 |
6 | 45303511410211 |
7 | 4433163401446 |
oct | 736565644637 |
9 | 203758326487 |
10 | 64254069151 |
11 | 25282824198 |
12 | 10552683967 |
13 | 609cbb747c |
14 | 3177861d5d |
15 | 1a10e62aa1 |
hex | ef5d7499f |
64254069151 has 2 divisors, whose sum is σ = 64254069152. Its totient is φ = 64254069150.
The previous prime is 64254069107. The next prime is 64254069161. The reversal of 64254069151 is 15196045246.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 64254069151 - 211 = 64254067103 is a prime.
It is a super-2 number, since 2×642540691512 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 64254069098 and 64254069107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (64254069101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32127034575 + 32127034576.
It is an arithmetic number, because the mean of its divisors is an integer number (32127034576).
Almost surely, 264254069151 is an apocalyptic number.
64254069151 is a deficient number, since it is larger than the sum of its proper divisors (1).
64254069151 is an equidigital number, since it uses as much as digits as its factorization.
64254069151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 43.
The spelling of 64254069151 in words is "sixty-four billion, two hundred fifty-four million, sixty-nine thousand, one hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •