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64255516993471 is a prime number
BaseRepresentation
bin11101001110000101001110…
…10000111110011110111111
322102111202201110101101022011
432213002213100332132333
531410230244322242341
6344354324344232051
716351210416520426
oct1647024720763677
9272452643341264
1064255516993471
1119523680228861
12725919676b627
1329b136671958b
1411c1dab0862bd
15766677da1b81
hex3a70a743e7bf

64255516993471 has 2 divisors, whose sum is σ = 64255516993472. Its totient is φ = 64255516993470.

The previous prime is 64255516993439. The next prime is 64255516993511. The reversal of 64255516993471 is 17439961555246.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 64255516993471 - 25 = 64255516993439 is a prime.

It is a super-3 number, since 3×642555169934713 (a number of 42 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 64255516993397 and 64255516993406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (64255516996471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32127758496735 + 32127758496736.

It is an arithmetic number, because the mean of its divisors is an integer number (32127758496736).

Almost surely, 264255516993471 is an apocalyptic number.

64255516993471 is a deficient number, since it is larger than the sum of its proper divisors (1).

64255516993471 is an equidigital number, since it uses as much as digits as its factorization.

64255516993471 is an evil number, because the sum of its binary digits is even.

The product of its digits is 244944000, while the sum is 67.

The spelling of 64255516993471 in words is "sixty-four trillion, two hundred fifty-five billion, five hundred sixteen million, nine hundred ninety-three thousand, four hundred seventy-one".