Base | Representation |
---|---|
bin | 11101001110000101001110… |
… | …10000111110011110111111 |
3 | 22102111202201110101101022011 |
4 | 32213002213100332132333 |
5 | 31410230244322242341 |
6 | 344354324344232051 |
7 | 16351210416520426 |
oct | 1647024720763677 |
9 | 272452643341264 |
10 | 64255516993471 |
11 | 19523680228861 |
12 | 725919676b627 |
13 | 29b136671958b |
14 | 11c1dab0862bd |
15 | 766677da1b81 |
hex | 3a70a743e7bf |
64255516993471 has 2 divisors, whose sum is σ = 64255516993472. Its totient is φ = 64255516993470.
The previous prime is 64255516993439. The next prime is 64255516993511. The reversal of 64255516993471 is 17439961555246.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 64255516993471 - 25 = 64255516993439 is a prime.
It is a super-3 number, since 3×642555169934713 (a number of 42 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 64255516993397 and 64255516993406.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (64255516996471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32127758496735 + 32127758496736.
It is an arithmetic number, because the mean of its divisors is an integer number (32127758496736).
Almost surely, 264255516993471 is an apocalyptic number.
64255516993471 is a deficient number, since it is larger than the sum of its proper divisors (1).
64255516993471 is an equidigital number, since it uses as much as digits as its factorization.
64255516993471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 244944000, while the sum is 67.
The spelling of 64255516993471 in words is "sixty-four trillion, two hundred fifty-five billion, five hundred sixteen million, nine hundred ninety-three thousand, four hundred seventy-one".
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