Base | Representation |
---|---|
bin | 1011111101111111… |
… | …11000101111101101 |
3 | 121120210222112111022 |
4 | 11332333320233231 |
5 | 101124431102023 |
6 | 2541335503525 |
7 | 315143034005 |
oct | 57677705755 |
9 | 17523875438 |
10 | 6425644013 |
11 | 27a81214a8 |
12 | 12b3b27ba5 |
13 | 7b5318729 |
14 | 44d56b005 |
15 | 2791b47c8 |
hex | 17eff8bed |
6425644013 has 2 divisors, whose sum is σ = 6425644014. Its totient is φ = 6425644012.
The previous prime is 6425643977. The next prime is 6425644019. The reversal of 6425644013 is 3104465246.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5673403684 + 752240329 = 75322^2 + 27427^2 .
It is a cyclic number.
It is not a de Polignac number, because 6425644013 - 210 = 6425642989 is a prime.
It is a super-3 number, since 3×64256440133 (a number of 30 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6425644019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3212822006 + 3212822007.
It is an arithmetic number, because the mean of its divisors is an integer number (3212822007).
Almost surely, 26425644013 is an apocalyptic number.
It is an amenable number.
6425644013 is a deficient number, since it is larger than the sum of its proper divisors (1).
6425644013 is an equidigital number, since it uses as much as digits as its factorization.
6425644013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69120, while the sum is 35.
The square root of 6425644013 is about 80160.1148514646. The cubic root of 6425644013 is about 1859.1119988451. Note that the first 3 decimals are identical.
The spelling of 6425644013 in words is "six billion, four hundred twenty-five million, six hundred forty-four thousand, thirteen".
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