Base | Representation |
---|---|
bin | 101110110000110111001… |
… | …1011101111011110100101 |
3 | 211202102112022101210202021 |
4 | 1131201232123233132211 |
5 | 1320300222200402213 |
6 | 21400325133143141 |
7 | 1232226056154505 |
oct | 135415633573645 |
9 | 24672468353667 |
10 | 6427123840933 |
11 | 2058800942a14 |
12 | 87975292aab1 |
13 | 3780c921bc53 |
14 | 18310842da05 |
15 | b22b6c29d8d |
hex | 5d86e6ef7a5 |
6427123840933 has 2 divisors, whose sum is σ = 6427123840934. Its totient is φ = 6427123840932.
The previous prime is 6427123840901. The next prime is 6427123840961. The reversal of 6427123840933 is 3390483217246.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5419202214724 + 1007921626209 = 2327918^2 + 1003953^2 .
It is a cyclic number.
It is not a de Polignac number, because 6427123840933 - 25 = 6427123840901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6427123840133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3213561920466 + 3213561920467.
It is an arithmetic number, because the mean of its divisors is an integer number (3213561920467).
Almost surely, 26427123840933 is an apocalyptic number.
It is an amenable number.
6427123840933 is a deficient number, since it is larger than the sum of its proper divisors (1).
6427123840933 is an equidigital number, since it uses as much as digits as its factorization.
6427123840933 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5225472, while the sum is 52.
The spelling of 6427123840933 in words is "six trillion, four hundred twenty-seven billion, one hundred twenty-three million, eight hundred forty thousand, nine hundred thirty-three".
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