Base | Representation |
---|---|
bin | 10010101101111010100… |
… | …01001001100001110011 |
3 | 2021111000112010021110111 |
4 | 21112331101021201303 |
5 | 41014110113011103 |
6 | 1211240415442151 |
7 | 64315151456356 |
oct | 11267521114163 |
9 | 2244015107414 |
10 | 643125516403 |
11 | 228825651347 |
12 | a4785526357 |
13 | 48853400056 |
14 | 231ad9ac29d |
15 | 11ae0e3d86d |
hex | 95bd449873 |
643125516403 has 2 divisors, whose sum is σ = 643125516404. Its totient is φ = 643125516402.
The previous prime is 643125516401. The next prime is 643125516419. The reversal of 643125516403 is 304615521346.
643125516403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 643125516403 - 21 = 643125516401 is a prime.
It is a super-2 number, since 2×6431255164032 (a number of 24 digits) contains 22 as substring.
Together with 643125516401, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (643125516401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 321562758201 + 321562758202.
It is an arithmetic number, because the mean of its divisors is an integer number (321562758202).
Almost surely, 2643125516403 is an apocalyptic number.
643125516403 is a deficient number, since it is larger than the sum of its proper divisors (1).
643125516403 is an equidigital number, since it uses as much as digits as its factorization.
643125516403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 40.
The spelling of 643125516403 in words is "six hundred forty-three billion, one hundred twenty-five million, five hundred sixteen thousand, four hundred three".
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