Base | Representation |
---|---|
bin | 101110110111111110111… |
… | …0001010111001000010111 |
3 | 211210212222212200121111221 |
4 | 1131233331301113020113 |
5 | 1321023030332132101 |
6 | 21411334240511211 |
7 | 1233310004442163 |
oct | 135577561271027 |
9 | 24725885617457 |
10 | 6442413552151 |
11 | 2064237551295 |
12 | 8806bb31b507 |
13 | 379694aa2955 |
14 | 183b58d09ca3 |
15 | b28ae1b9aa1 |
hex | 5dbfdc57217 |
6442413552151 has 2 divisors, whose sum is σ = 6442413552152. Its totient is φ = 6442413552150.
The previous prime is 6442413552109. The next prime is 6442413552161. The reversal of 6442413552151 is 1512553142446.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 6442413552151 - 225 = 6442379997719 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 6442413552098 and 6442413552107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6442413552161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3221206776075 + 3221206776076.
It is an arithmetic number, because the mean of its divisors is an integer number (3221206776076).
Almost surely, 26442413552151 is an apocalyptic number.
6442413552151 is a deficient number, since it is larger than the sum of its proper divisors (1).
6442413552151 is an equidigital number, since it uses as much as digits as its factorization.
6442413552151 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 576000, while the sum is 43.
Adding to 6442413552151 its reverse (1512553142446), we get a palindrome (7954966694597).
The spelling of 6442413552151 in words is "six trillion, four hundred forty-two billion, four hundred thirteen million, five hundred fifty-two thousand, one hundred fifty-one".
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