Base | Representation |
---|---|
bin | 101110111000000101111… |
… | …1100010111010010111111 |
3 | 211210220121110002100011201 |
4 | 1131300023330113102333 |
5 | 1321024022214124224 |
6 | 21411414013000331 |
7 | 1233315622426351 |
oct | 135601374272277 |
9 | 24726543070151 |
10 | 6442651317439 |
11 | 2064349788927 |
12 | 880766a830a7 |
13 | 37970212057c |
14 | 183b7c71d0d1 |
15 | b28c4ed3a44 |
hex | 5dc0bf174bf |
6442651317439 has 2 divisors, whose sum is σ = 6442651317440. Its totient is φ = 6442651317438.
The previous prime is 6442651317413. The next prime is 6442651317481. The reversal of 6442651317439 is 9347131562446.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 6442651317439 - 211 = 6442651315391 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 6442651317439.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6442651317139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3221325658719 + 3221325658720.
It is an arithmetic number, because the mean of its divisors is an integer number (3221325658720).
Almost surely, 26442651317439 is an apocalyptic number.
6442651317439 is a deficient number, since it is larger than the sum of its proper divisors (1).
6442651317439 is an equidigital number, since it uses as much as digits as its factorization.
6442651317439 is an evil number, because the sum of its binary digits is even.
The product of its digits is 13063680, while the sum is 55.
The spelling of 6442651317439 in words is "six trillion, four hundred forty-two billion, six hundred fifty-one million, three hundred seventeen thousand, four hundred thirty-nine".
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