Base | Representation |
---|---|
bin | 11101010011001101000101… |
… | …01010101101101010110001 |
3 | 22110010121001100112001011122 |
4 | 32221212202222231222301 |
5 | 31421121240034412033 |
6 | 345011234325152025 |
7 | 16400011315330124 |
oct | 1651464252555261 |
9 | 273117040461148 |
10 | 64431533513393 |
11 | 19591294a3a442 |
12 | 728731a25b615 |
13 | 29c4b37ca4807 |
14 | 11ca707bcc3bb |
15 | 76b02a9e9a98 |
hex | 3a99a2aadab1 |
64431533513393 has 2 divisors, whose sum is σ = 64431533513394. Its totient is φ = 64431533513392.
The previous prime is 64431533513341. The next prime is 64431533513491. The reversal of 64431533513393 is 39331533513446.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 37624581996544 + 26806951516849 = 6133888^2 + 5177543^2 .
It is a cyclic number.
It is not a de Polignac number, because 64431533513393 - 210 = 64431533512369 is a prime.
It is not a weakly prime, because it can be changed into another prime (64431533513093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32215766756696 + 32215766756697.
It is an arithmetic number, because the mean of its divisors is an integer number (32215766756697).
Almost surely, 264431533513393 is an apocalyptic number.
It is an amenable number.
64431533513393 is a deficient number, since it is larger than the sum of its proper divisors (1).
64431533513393 is an equidigital number, since it uses as much as digits as its factorization.
64431533513393 is an evil number, because the sum of its binary digits is even.
The product of its digits is 15746400, while the sum is 53.
Adding to 64431533513393 its sum of digits (53), we get a palindrome (64431533513446).
The spelling of 64431533513393 in words is "sixty-four trillion, four hundred thirty-one billion, five hundred thirty-three million, five hundred thirteen thousand, three hundred ninety-three".
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