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64433450113 is a prime number
BaseRepresentation
bin111100000000100010…
…000110110010000001
320011022110220101222021
4330000202012302001
52023424430400423
645333400241441
74440502201144
oct740042066201
9204273811867
1064433450113
112536500381a
12105a2770281
1360cb102656
1431935d805b
151a21a9795d
hexf00886c81

64433450113 has 2 divisors, whose sum is σ = 64433450114. Its totient is φ = 64433450112.

The previous prime is 64433450093. The next prime is 64433450153. The reversal of 64433450113 is 31105433446.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 55692696049 + 8740754064 = 235993^2 + 93492^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-64433450113 is a prime.

It is a super-3 number, since 3×644334501133 (a number of 33 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (64433450153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32216725056 + 32216725057.

It is an arithmetic number, because the mean of its divisors is an integer number (32216725057).

Almost surely, 264433450113 is an apocalyptic number.

It is an amenable number.

64433450113 is a deficient number, since it is larger than the sum of its proper divisors (1).

64433450113 is an equidigital number, since it uses as much as digits as its factorization.

64433450113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 51840, while the sum is 34.

Adding to 64433450113 its reverse (31105433446), we get a palindrome (95538883559).

The spelling of 64433450113 in words is "sixty-four billion, four hundred thirty-three million, four hundred fifty thousand, one hundred thirteen".