Base | Representation |
---|---|
bin | 111100000100110111… |
… | …000000000000100111 |
3 | 20011111112111011110012 |
4 | 330010313000000213 |
5 | 2024102021130023 |
6 | 45344512120435 |
7 | 4442343155444 |
oct | 740467000047 |
9 | 204445434405 |
10 | 64506036263 |
11 | 253a1a80879 |
12 | 10602b3611b |
13 | 6110168336 |
14 | 319d0d09cb |
15 | 1a28134978 |
hex | f04dc0027 |
64506036263 has 2 divisors, whose sum is σ = 64506036264. Its totient is φ = 64506036262.
The previous prime is 64506036247. The next prime is 64506036269. The reversal of 64506036263 is 36263060546.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 64506036263 - 24 = 64506036247 is a prime.
It is a super-3 number, since 3×645060362633 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 64506036263.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (64506036269) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32253018131 + 32253018132.
It is an arithmetic number, because the mean of its divisors is an integer number (32253018132).
Almost surely, 264506036263 is an apocalyptic number.
64506036263 is a deficient number, since it is larger than the sum of its proper divisors (1).
64506036263 is an equidigital number, since it uses as much as digits as its factorization.
64506036263 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 466560, while the sum is 41.
The spelling of 64506036263 in words is "sixty-four billion, five hundred six million, thirty-six thousand, two hundred sixty-three".
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