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645136624211581 is a prime number
BaseRepresentation
bin1001001010101111111001001…
…1010100010101011001111101
310010121020110101120111101001101
42102223332103110111121331
51134024404301244232311
610204031401304213101
7252613403646610525
oct22253762324253175
93117213346441041
10645136624211581
111776189a6765927
126043397216a191
13218c9179530b98
14b544aca254685
154e8b73dca8ec1
hex24abf9351567d

645136624211581 has 2 divisors, whose sum is σ = 645136624211582. Its totient is φ = 645136624211580.

The previous prime is 645136624211509. The next prime is 645136624211603. The reversal of 645136624211581 is 185112426631546.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 493828395062500 + 151308229149081 = 22222250^2 + 12300741^2 .

It is a cyclic number.

It is not a de Polignac number, because 645136624211581 - 211 = 645136624209533 is a prime.

It is a super-2 number, since 2×6451366242115812 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (645136624211501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 322568312105790 + 322568312105791.

It is an arithmetic number, because the mean of its divisors is an integer number (322568312105791).

Almost surely, 2645136624211581 is an apocalyptic number.

It is an amenable number.

645136624211581 is a deficient number, since it is larger than the sum of its proper divisors (1).

645136624211581 is an equidigital number, since it uses as much as digits as its factorization.

645136624211581 is an evil number, because the sum of its binary digits is even.

The product of its digits is 8294400, while the sum is 55.

The spelling of 645136624211581 in words is "six hundred forty-five trillion, one hundred thirty-six billion, six hundred twenty-four million, two hundred eleven thousand, five hundred eighty-one".