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64544025433 is a prime number
BaseRepresentation
bin111100000111000111…
…111010101101011001
320011121011222012210111
4330013013322231121
52024141232303213
645352350244321
74443314110156
oct740707725531
9204534865714
1064544025433
1125411468688
12106137b66a1
136117ca9834
1431a417d22d
151a2b63aa3d
hexf071fab59

64544025433 has 2 divisors, whose sum is σ = 64544025434. Its totient is φ = 64544025432.

The previous prime is 64544025431. The next prime is 64544025467. The reversal of 64544025433 is 33452044546.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 51385182489 + 13158842944 = 226683^2 + 114712^2 .

It is a cyclic number.

It is not a de Polignac number, because 64544025433 - 21 = 64544025431 is a prime.

Together with 64544025431, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (64544025431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32272012716 + 32272012717.

It is an arithmetic number, because the mean of its divisors is an integer number (32272012717).

Almost surely, 264544025433 is an apocalyptic number.

It is an amenable number.

64544025433 is a deficient number, since it is larger than the sum of its proper divisors (1).

64544025433 is an equidigital number, since it uses as much as digits as its factorization.

64544025433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 691200, while the sum is 40.

Adding to 64544025433 its reverse (33452044546), we get a palindrome (97996069979).

The spelling of 64544025433 in words is "sixty-four billion, five hundred forty-four million, twenty-five thousand, four hundred thirty-three".