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6475325351917 is a prime number
BaseRepresentation
bin101111000111010011101…
…1101111010011111101101
3211221000221120001021020211
41132032213131322133231
51322042431242230132
621434420130542421
71235553412225162
oct136164735723755
924830846037224
106475325351917
112077196393604
12886b65437a11
1337c80b4aa596
1418559bd5c069
15b3688764147
hex5e3a777a7ed

6475325351917 has 2 divisors, whose sum is σ = 6475325351918. Its totient is φ = 6475325351916.

The previous prime is 6475325351893. The next prime is 6475325352017. The reversal of 6475325351917 is 7191535235746.

6475325351917 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6457321347876 + 18004004041 = 2541126^2 + 134179^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-6475325351917 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (6475325391917) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3237662675958 + 3237662675959.

It is an arithmetic number, because the mean of its divisors is an integer number (3237662675959).

Almost surely, 26475325351917 is an apocalyptic number.

It is an amenable number.

6475325351917 is a deficient number, since it is larger than the sum of its proper divisors (1).

6475325351917 is an equidigital number, since it uses as much as digits as its factorization.

6475325351917 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 23814000, while the sum is 58.

The spelling of 6475325351917 in words is "six trillion, four hundred seventy-five billion, three hundred twenty-five million, three hundred fifty-one thousand, nine hundred seventeen".