Base | Representation |
---|---|
bin | 10010110111100100111… |
… | …11110001110111111111 |
3 | 2021222102002020201201012 |
4 | 21123302133301313333 |
5 | 41110221224331143 |
6 | 1213455304305435 |
7 | 64560545631314 |
oct | 11336237616777 |
9 | 2258362221635 |
10 | 648313511423 |
11 | 22aa48091836 |
12 | a5792a7227b |
13 | 4919c1a18a6 |
14 | 23542a08d0b |
15 | 11ce662c418 |
hex | 96f27f1dff |
648313511423 has 2 divisors, whose sum is σ = 648313511424. Its totient is φ = 648313511422.
The previous prime is 648313511389. The next prime is 648313511441. The reversal of 648313511423 is 324115313846.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 648313511423 - 212 = 648313507327 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (648313511323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 324156755711 + 324156755712.
It is an arithmetic number, because the mean of its divisors is an integer number (324156755712).
Almost surely, 2648313511423 is an apocalyptic number.
648313511423 is a deficient number, since it is larger than the sum of its proper divisors (1).
648313511423 is an equidigital number, since it uses as much as digits as its factorization.
648313511423 is an evil number, because the sum of its binary digits is even.
The product of its digits is 207360, while the sum is 41.
The spelling of 648313511423 in words is "six hundred forty-eight billion, three hundred thirteen million, five hundred eleven thousand, four hundred twenty-three".
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