Base | Representation |
---|---|
bin | 11101100000101111001001… |
… | …01011011110010111011011 |
3 | 22111210001012111020200221201 |
4 | 32300113210223132113123 |
5 | 32001231011323231313 |
6 | 350005012300415031 |
7 | 16445421463654156 |
oct | 1660274453362733 |
9 | 274701174220851 |
10 | 64896497477083 |
11 | 197504a4a83228 |
12 | 7341461847477 |
13 | 2a299375c224c |
14 | 1205015c04c9d |
15 | 7781908300dd |
hex | 3b05e4ade5db |
64896497477083 has 2 divisors, whose sum is σ = 64896497477084. Its totient is φ = 64896497477082.
The previous prime is 64896497476997. The next prime is 64896497477153. The reversal of 64896497477083 is 38077479469846.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 64896497477083 - 217 = 64896497346011 is a prime.
It is a super-2 number, since 2×648964974770832 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 64896497476988 and 64896497477006.
It is not a weakly prime, because it can be changed into another prime (64896437477083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32448248738541 + 32448248738542.
It is an arithmetic number, because the mean of its divisors is an integer number (32448248738542).
Almost surely, 264896497477083 is an apocalyptic number.
64896497477083 is a deficient number, since it is larger than the sum of its proper divisors (1).
64896497477083 is an equidigital number, since it uses as much as digits as its factorization.
64896497477083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12290310144, while the sum is 82.
The spelling of 64896497477083 in words is "sixty-four trillion, eight hundred ninety-six billion, four hundred ninety-seven million, four hundred seventy-seven thousand, eighty-three".
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