Base | Representation |
---|---|
bin | 111100011100100101… |
… | …101100000100001111 |
3 | 20012112021121111121222 |
4 | 330130211230010033 |
5 | 2030410430320221 |
6 | 45452213113555 |
7 | 4455246116636 |
oct | 743445540417 |
9 | 205467544558 |
10 | 64904151311 |
11 | 2558677957a |
12 | 106b43288bb |
13 | 617479997c |
14 | 31d9d2451d |
15 | 1a4d0749ab |
hex | f1c96c10f |
64904151311 has 2 divisors, whose sum is σ = 64904151312. Its totient is φ = 64904151310.
The previous prime is 64904151289. The next prime is 64904151317. The reversal of 64904151311 is 11315140946.
64904151311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 64904151311 - 222 = 64899957007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (64904151317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32452075655 + 32452075656.
It is an arithmetic number, because the mean of its divisors is an integer number (32452075656).
Almost surely, 264904151311 is an apocalyptic number.
64904151311 is a deficient number, since it is larger than the sum of its proper divisors (1).
64904151311 is an equidigital number, since it uses as much as digits as its factorization.
64904151311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 35.
The spelling of 64904151311 in words is "sixty-four billion, nine hundred four million, one hundred fifty-one thousand, three hundred eleven".
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