Base | Representation |
---|---|
bin | 101111001111010100110… |
… | …1000110110000001100111 |
3 | 211222200101101112100202002 |
4 | 1132132221220312001213 |
5 | 1322333211130001212 |
6 | 21450344335435515 |
7 | 1240033143245225 |
oct | 136365150660147 |
9 | 24880341470662 |
10 | 6492541640807 |
11 | 2083520550232 |
12 | 88a36b085b9b |
13 | 38132323c181 |
14 | 18635265db15 |
15 | b3d44e11ac2 |
hex | 5e7a9a36067 |
6492541640807 has 2 divisors, whose sum is σ = 6492541640808. Its totient is φ = 6492541640806.
The previous prime is 6492541640779. The next prime is 6492541640831. The reversal of 6492541640807 is 7080461452946.
6492541640807 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 6492541640807 - 26 = 6492541640743 is a prime.
It is a super-2 number, since 2×64925416408072 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6492541643807) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3246270820403 + 3246270820404.
It is an arithmetic number, because the mean of its divisors is an integer number (3246270820404).
Almost surely, 26492541640807 is an apocalyptic number.
6492541640807 is a deficient number, since it is larger than the sum of its proper divisors (1).
6492541640807 is an equidigital number, since it uses as much as digits as its factorization.
6492541640807 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11612160, while the sum is 56.
The spelling of 6492541640807 in words is "six trillion, four hundred ninety-two billion, five hundred forty-one million, six hundred forty thousand, eight hundred seven".
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