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65085403 is a prime number
BaseRepresentation
bin1111100001000…
…1111111011011
311112110200101111
43320101333123
5113130213103
610243001151
71420134235
oct370217733
9145420344
1065085403
1133814699
12199691b7
131063a896
148903255
155aa986d
hex3e11fdb

65085403 has 2 divisors, whose sum is σ = 65085404. Its totient is φ = 65085402.

The previous prime is 65085389. The next prime is 65085407. The reversal of 65085403 is 30458056.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 65085403 - 213 = 65077211 is a prime.

It is a super-2 number, since 2×650854032 = 8472219367344818, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (65085407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32542701 + 32542702.

It is an arithmetic number, because the mean of its divisors is an integer number (32542702).

Almost surely, 265085403 is an apocalyptic number.

65085403 is a deficient number, since it is larger than the sum of its proper divisors (1).

65085403 is an equidigital number, since it uses as much as digits as its factorization.

65085403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 31.

The square root of 65085403 is about 8067.5524789121. The cubic root of 65085403 is about 402.2485921474.

It can be divided in two parts, 6508 and 5403, that added together give a palindrome (11911).

The spelling of 65085403 in words is "sixty-five million, eighty-five thousand, four hundred three".