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65113431324041 is a prime number
BaseRepresentation
bin11101100111000011001101…
…11100011011010110001001
322112112210010222112221110002
432303201212330123112021
532013304301404332131
6350252410345532345
716500201346150322
oct1663414674332611
9275483128487402
1065113431324041
11198244a652a271
1273775044a40b5
132a44229cb1cb9
141211714ca5449
1577db3a7606cb
hex3b3866f1b589

65113431324041 has 2 divisors, whose sum is σ = 65113431324042. Its totient is φ = 65113431324040.

The previous prime is 65113431324031. The next prime is 65113431324091. The reversal of 65113431324041 is 14042313431156.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 33715395798016 + 31398035526025 = 5806496^2 + 5603395^2 .

It is a cyclic number.

It is not a de Polignac number, because 65113431324041 - 238 = 64838553417097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 65113431323986 and 65113431324004.

It is not a weakly prime, because it can be changed into another prime (65113431324031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32556715662020 + 32556715662021.

It is an arithmetic number, because the mean of its divisors is an integer number (32556715662021).

Almost surely, 265113431324041 is an apocalyptic number.

It is an amenable number.

65113431324041 is a deficient number, since it is larger than the sum of its proper divisors (1).

65113431324041 is an equidigital number, since it uses as much as digits as its factorization.

65113431324041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 103680, while the sum is 38.

Adding to 65113431324041 its reverse (14042313431156), we get a palindrome (79155744755197).

The spelling of 65113431324041 in words is "sixty-five trillion, one hundred thirteen billion, four hundred thirty-one million, three hundred twenty-four thousand, forty-one".