Search a number
-
+
65124131 is a prime number
BaseRepresentation
bin1111100001101…
…1011100100011
311112112122111212
43320123130203
5113132433011
610243500335
71420355162
oct370333443
9145478455
1065124131
11338407a6
12199876ab
13106523b7
1489133d9
155ab608b
hex3e1b723

65124131 has 2 divisors, whose sum is σ = 65124132. Its totient is φ = 65124130.

The previous prime is 65124091. The next prime is 65124133. The reversal of 65124131 is 13142156.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-65124131 is a prime.

It is a super-2 number, since 2×651241312 = 8482304877010322, which contains 22 as substring.

Together with 65124133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 65124097 and 65124106.

It is not a weakly prime, because it can be changed into another prime (65124133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32562065 + 32562066.

It is an arithmetic number, because the mean of its divisors is an integer number (32562066).

Almost surely, 265124131 is an apocalyptic number.

65124131 is a deficient number, since it is larger than the sum of its proper divisors (1).

65124131 is an equidigital number, since it uses as much as digits as its factorization.

65124131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 720, while the sum is 23.

The square root of 65124131 is about 8069.9523542584. The cubic root of 65124131 is about 402.3283601339.

Adding to 65124131 its reverse (13142156), we get a palindrome (78266287).

The spelling of 65124131 in words is "sixty-five million, one hundred twenty-four thousand, one hundred thirty-one".