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65140140527471 = 251259522472221
BaseRepresentation
bin11101100111110100111101…
…11011111100111101101111
322112122100002101122001120202
432303322132323330331233
532014224001433334341
6350312544544504115
716502135256505142
oct1663723673747557
9275570071561522
1065140140527471
1119834862145109
12738071931b03b
132a468c5667b99
141212b2a24c059
1577e6a050379b
hex3b3e9eefcf6f

65140140527471 has 4 divisors (see below), whose sum is σ = 65399662999944. Its totient is φ = 64880618055000.

The previous prime is 65140140527443. The next prime is 65140140527479. The reversal of 65140140527471 is 17472504104156.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 65140140527471 - 218 = 65140140265327 is a prime.

It is a super-3 number, since 3×651401405274713 (a number of 42 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (65140140527479) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 129761235860 + ... + 129761236361.

It is an arithmetic number, because the mean of its divisors is an integer number (16349915749986).

Almost surely, 265140140527471 is an apocalyptic number.

65140140527471 is a deficient number, since it is larger than the sum of its proper divisors (259522472473).

65140140527471 is a wasteful number, since it uses less digits than its factorization.

65140140527471 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 259522472472.

The product of its (nonzero) digits is 940800, while the sum is 47.

The spelling of 65140140527471 in words is "sixty-five trillion, one hundred forty billion, one hundred forty million, five hundred twenty-seven thousand, four hundred seventy-one".

Divisors: 1 251 259522472221 65140140527471