Base | Representation |
---|---|
bin | 11101101011001100101000… |
… | …10111011111101001100001 |
3 | 22120001101221202220022011101 |
4 | 32311212110113133221201 |
5 | 32023123114343040131 |
6 | 350442054213314401 |
7 | 16513404466120321 |
oct | 1665462427375141 |
9 | 276041852808141 |
10 | 65255927315041 |
11 | 19879979829391 |
12 | 739b052035a01 |
13 | 2a547b89cb738 |
14 | 1218591bbd281 |
15 | 7826ca669c61 |
hex | 3b59945dfa61 |
65255927315041 has 2 divisors, whose sum is σ = 65255927315042. Its totient is φ = 65255927315040.
The previous prime is 65255927315011. The next prime is 65255927315077. The reversal of 65255927315041 is 14051372955256.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 36659743263441 + 28596184051600 = 6054729^2 + 5347540^2 .
It is a cyclic number.
It is not a de Polignac number, because 65255927315041 - 25 = 65255927315009 is a prime.
It is not a weakly prime, because it can be changed into another prime (65255927315011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32627963657520 + 32627963657521.
It is an arithmetic number, because the mean of its divisors is an integer number (32627963657521).
Almost surely, 265255927315041 is an apocalyptic number.
It is an amenable number.
65255927315041 is a deficient number, since it is larger than the sum of its proper divisors (1).
65255927315041 is an equidigital number, since it uses as much as digits as its factorization.
65255927315041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11340000, while the sum is 55.
The spelling of 65255927315041 in words is "sixty-five trillion, two hundred fifty-five billion, nine hundred twenty-seven million, three hundred fifteen thousand, forty-one".
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